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I need to join 3 tables where A.id == B.id and B.id == C.id using JPA @SecondaryTables where I need to map these tables to a single entity. what is the way I should I should try?

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Since A.ID = B.ID = C.ID, you can just have 2 secondary tables, with the relationship A.ID = B.ID, and A.ID = C.ID. Your "main" table will be A, and B and C are your secondary tables. You can reference the table as follows in your column declaration. (many other parameters in the annotations left out for brevity)

@Entity
@Table(name = "A")
@SecondaryTables({
  @SecondaryTable(name="B", @PrimaryKeyJoinColumn(name="ID", referencedColumnName="ID")),  
  @SecondaryTable(name="C",  @PrimaryKeyJoinColumn(name="ID", referencedColumnName="ID"))
})
public Claass Blah {
  @ID
  private int id;

  @Column(table = "B")
  private String someColumn;

  @Column(table = "C")
  private String someOtherColumn;

etc...
}
  • I have tried that but C.id is referencing to A.id. It is like this A.id = B.id and A.id = C.id what I need is A.id == B.id and B.id == C.id – Jayampathy Wijesena Mar 15 '18 at 4:29
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    I'm not understanding you. If A.id = B.id, and B.id = C.id, then by transitivity, A.id = C.id – Jeff Wang Mar 15 '18 at 5:31
  • yes that is correct but what I need is something like this A.id = B.id and B.did = C.did There is no relationship like A.id = C.id – Jayampathy Wijesena Mar 15 '18 at 5:39
  • I see, so the id for the two relationships is separate? Do you have to have the same class? If not, you can create 2 classes, one of which has a secondary table, the other of which has a @OneToOne relationship with the first one. – Jeff Wang Mar 15 '18 at 6:53

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